RobberSEARCH AGGREGATION
House Robber I You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is tha...
House Robber I Problem You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them...
House Robber I You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is tha...
題目詳情 You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent ...
... tonight without alerting the police. Notice This is an extension of House Robber. Example nums = [3,6,4], return 6 Note 因?yàn)槿×岁?duì)首就不能取隊(duì)尾，所以對(duì)dp數(shù)組循環(huán)兩次，一個(gè)從0取到len-2，一個(gè)從1取到len-1，比較兩次循環(huán)后隊(duì)尾元素，取較大者。注意，...
LeetCode[337] House Robber III The thief has found himself a new place for his thievery again. There is only one entrance to this area, called the root. Besides the root, each house has one and only ...
...來(lái)進(jìn)行劃分的。 Solution public class Solution { public int houseRobber3(TreeNode root) { int[] A = dfs(root); return Math.max(A[0], A[1]); } public int[] dfs(TreeNode root) { ...
題目要求 The thief has found himself a new place for his thievery again. There is only one entrance to this area, called the root. Besides the root, each house has one and only one parent house. After a t...
Description The thief has found himself a new place for his thievery again. There is only one entrance to this area, called the root. Besides the root, each house has one and only one parent house. Af...
...tock 167 Two Sum II - Input array is sorted 169 Majority Element 198 House Robber(03-25更新) 217 Contains Duplicate 219 Contains Duplicate II 268 Missing Number 283 Move Zeroes 414 Third Maximum Num...
... 191 - 位1的個(gè)數(shù)（number-of-1-bits） ? 198 - 打家劫舍（house-robber） ? 202 - 快樂(lè)數(shù)（happy-number） ? 203 - 移除鏈表元素（remove-linked-list-elements） ? 204 - 計(jì)數(shù)質(zhì)數(shù)（count-primes） ? 205 - 同構(gòu)字符串（isomorphic-strings） ? 206 - ...
...spatch(addmoney(earn.money + 1000000)) return dispatch(setLastJob(robber)) } } // 定義一個(gè)賺錢的方式2，建材轉(zhuǎn)移者 export function moveBrick(){ return (dispatch, getState) => { console.log(...
...ts ↗ Easy 202 快樂(lè)數(shù) Happy Number ↗ Easy 198 打家劫舍 House Robber ↗ Easy 191 位 1 的個(gè)數(shù) Number of 1 Bits ↗ Easy 190 顛倒二進(jìn)制位 Reverse Bits ↗ Easy 189 旋轉(zhuǎn)數(shù)組 Rotate Array ↗ Easy 172 階乘后的零 Factorial Tr...
... 191 - 位1的個(gè)數(shù)（number-of-1-bits） ? 198 - 打家劫舍（house-robber） ? 202 - 快樂(lè)數(shù)（happy-number） ? 203 - 移除鏈表元素（remove-linked-list-elements） ? 204 - 計(jì)數(shù)質(zhì)數(shù)（count-primes） ? 205 - 同構(gòu)字符串（isomorphic-strings） ? 206 - ...
...）+動(dòng)規(guī)） [198. 打家劫舍](https://leetcode-cn.com/problems/house-robber/)（動(dòng)規(guī)） [136. 只出現(xiàn)一次的數(shù)字](https://leetcode-cn.com/problems/single-number/)（異或運(yùn)算） [69. Sqrt(x)](https://leetcode-cn.com/problems/sqr...
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