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  • [LintCode/LeetCode] Single Number I & II [位運(yùn)算]

    摘要:整個(gè)過程相當(dāng)于,直接在和里去掉既是又是的。所以最后返回的,一定是只出現(xiàn)過一次的,而出現(xiàn)兩次的都在里,出現(xiàn)三次的都被消去了。 Single Number I Problem Given 2*n + 1 numbers, every numbers occurs twice except one, find it. Example Given [1,2,2,1,3,4,3], return...

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  • [LintCode/LeetCode] Maximal Square

    摘要:類似這種需要遍歷矩陣或數(shù)組來判斷,或者計(jì)算最優(yōu)解最短步數(shù),最大距離,的題目,都可以使用遞歸。 Problem Given a 2D binary matrix filled with 0s and 1s, find the largest square containing all 1s and return its area. Example For example, given t...

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  • LeetCode[397] Integer Replacement

    摘要:復(fù)雜度思路利用位的操作。如果一個(gè)數(shù)是奇數(shù),那么末位的位一定是。對(duì)于偶數(shù),操作是直接除以。對(duì)于奇數(shù)的操作如果倒數(shù)第二位是,那么的操作比的操作能消掉更多的。還有一個(gè)的地方是,為了防止越界,可以將先轉(zhuǎn)換成。 LeetCode[397] Integer Replacement Given a positive integer n and you can do operations as fo...

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  • [CS101] Programming Languages and OOP 編程語(yǔ)言及面向?qū)ο蠡A(chǔ)題

    摘要:編程語(yǔ)言及面向?qū)ο蠡A(chǔ)題 編程語(yǔ)言及面向?qū)ο蠡A(chǔ)題 Design Pattern What is singleton? Whats its cons and pros? How to implement it?Definition: Singleton pattern is a design pattern that ensure that only one instance of a...

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  • css將兩個(gè)元素水平對(duì)齊,兼容IE8

    摘要:實(shí)現(xiàn)元素水平對(duì)齊實(shí)現(xiàn)水平對(duì)齊,如圖有人會(huì)說實(shí)現(xiàn)這種水平對(duì)齊要兼容還不簡(jiǎn)單嗎使用,或者,不就可以了嗎是的,最常用的最簡(jiǎn)單方式就是上面這兩種,但還有一種方式也可以實(shí)現(xiàn),那就是使用示例代碼關(guān)鍵點(diǎn)在于將兩個(gè)元素設(shè)置為即使寬度 css實(shí)現(xiàn)元素水平對(duì)齊 css實(shí)現(xiàn)水平對(duì)齊,如圖showImg(https://segmentfault.com/img/bVbgwDJ?w=1000&h=601); 有...

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