成人无码视频,亚洲精品久久久久av无码,午夜精品久久久久久毛片,亚洲 中文字幕 日韩 无码

資訊專欄INFORMATION COLUMN

[LeetCode] Sum Root to Leaf Numbers

魏明 / 1013人閱讀

Problem

Given a binary tree containing digits from 0-9 only, each root-to-leaf path could represent a number.

An example is the root-to-leaf path 1->2->3 which represents the number 123.

Find the total sum of all root-to-leaf numbers.

Note: A leaf is a node with no children.

Example

Input: [1,2,3]

    1
   / 
  2   3

Output: 25
Explanation:
The root-to-leaf path 1->2 represents the number 12.
The root-to-leaf path 1->3 represents the number 13.
Therefore, sum = 12 + 13 = 25.
Example 2:

Input: [4,9,0,5,1]

    4
   / 
  9   0
 / 
5   1

Output: 1026
Explanation:
The root-to-leaf path 4->9->5 represents the number 495.
The root-to-leaf path 4->9->1 represents the number 491.
The root-to-leaf path 4->0 represents the number 40.
Therefore, sum = 495 + 491 + 40 = 1026.

Solution
class Solution {
    public int sumNumbers(TreeNode root) {
        if (root == null) return 0;
        return sum(root, 0);
    }
    private int sum(TreeNode root, int cur) {
        if (root == null) return 0;
        if (root.left == null && root.right == null) return cur*10+root.val;
        return sum(root.left, cur*10+root.val)+sum(root.right, cur*10+root.val);
    }
}

文章版權(quán)歸作者所有,未經(jīng)允許請勿轉(zhuǎn)載,若此文章存在違規(guī)行為,您可以聯(lián)系管理員刪除。

轉(zhuǎn)載請注明本文地址:http://m.hztianpu.com/yun/71120.html

相關(guān)文章

  • [Leetcode-Tree] Sum Root to Leaf Numbers

    摘要:解題思路本題要求所有從根結(jié)點(diǎn)到葉子節(jié)點(diǎn)的路徑和,我們用遞歸實(shí)現(xiàn)。結(jié)束條件當(dāng)遇到葉子節(jié)點(diǎn)時,直接結(jié)束,返回計算好的如果遇到空節(jié)點(diǎn),則返回數(shù)值。 Sum Root to Leaf NumbersGiven a binary tree containing digits from 0-9 only, each root-to-leaf path could represent a numbe...

    BigNerdCoding 評論0 收藏0
  • [Leetcode] Sum Root to Leaf Numbers 累加葉子節(jié)點(diǎn)

    摘要:遞歸法復(fù)雜度時間空間遞歸??臻g思路簡單的二叉樹遍歷,遍歷時將自身的數(shù)值加入子節(jié)點(diǎn)。一旦遍歷到葉子節(jié)點(diǎn)便將該葉子結(jié)點(diǎn)的值加入結(jié)果中。 Sum Root to Leaf Numbers Given a binary tree containing digits from 0-9 only, each root-to-leaf path could represent a number.An...

    wean 評論0 收藏0
  • [LeetCode] Path Sum (I & II & III)

    摘要: 112. Path Sum Problem Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum. Note: A leaf is a node...

    張金寶 評論0 收藏0
  • [Leetcode-Tree] Path Sum I II III

    摘要:解題思路利用遞歸,對于每個根節(jié)點(diǎn),只要左子樹和右子樹中有一個滿足,就返回每次訪問一個節(jié)點(diǎn),就將該節(jié)點(diǎn)的作為新的進(jìn)行下一層的判斷。代碼解題思路本題的不同點(diǎn)是可以不從開始,不到結(jié)束。代碼當(dāng)前節(jié)點(diǎn)開始當(dāng)前節(jié)點(diǎn)左節(jié)點(diǎn)開始當(dāng)前節(jié)點(diǎn)右節(jié)點(diǎn)開始 Path SumGiven a binary tree and a sum, determine if the tree has a root-to-lea...

    notebin 評論0 收藏0
  • LeetCode 之 JavaScript 解答第112題 —— 路徑總和(Path Sum

    摘要:小鹿題目路徑總和給定一個二叉樹和一個目標(biāo)和,判斷該樹中是否存在根節(jié)點(diǎn)到葉子節(jié)點(diǎn)的路徑,這條路徑上所有節(jié)點(diǎn)值相加等于目標(biāo)和。說明葉子節(jié)點(diǎn)是指沒有子節(jié)點(diǎn)的節(jié)點(diǎn)。 Time:2019/4/26Title: Path SumDifficulty: EasyAuthor: 小鹿 題目:Path Sum(路徑總和) Given a binary tree and a sum, determin...

    lylwyy2016 評論0 收藏0

發(fā)表評論

0條評論

魏明

|高級講師

TA的文章

閱讀更多
最新活動
閱讀需要支付1元查看
<